How Many 3 Digit Numbers Contain at Least One 7
Case i 78972 ways 0 cant on hundreds Case ii 78972 ways Case iii 79981 ways Total 225 ways A Was this answer helpful. How many four-digit numbers contain at least one 3 and at least one 7. How Many Three Digit Numbers Are Divisible By 7 Ex 5 2 13 Ap So the number of 3-digit numbers with at least one three is 900 - 648 252. . Then I add all the numbers of type yz5x where z can be 0 1 2 3 4 6 7 8 9. How many three digit numbers have at least one 2 and at least one 3 is A 52 B 48 C 54 D 46. Choose the 2nd digit 9 ways can choose 0. Then I add all the numbers of type y5xx where y can be 1 2 3 4 6 7 8 9. The remaining six digit numbers contain at least one 7 and hence the number of six digit numbers that contain at least one 7 is 900 000 - 472 392 427 608. And at least one 4. So there are 8x9x9x9x9x9 or 472392 6-digit numbers that do not contain 7. 2 How many of them have the digit 7 in the tens position. Thus ...